2t=50t-4.9t^2

Solution for 2t=50t-4.9t^2 equation:

2t=50t-4.9t^2

We move all terms to the left:

2t-(50t-4.9t^2)=0

We get rid of parentheses

4.9t^2-50t+2t=0

We add all the numbers together, and all the variables

4.9t^2-48t=0

a = 4.9; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·4.9·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*4.9}=\frac{0}{9.8}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*4.9}=\frac{96}{9.8}
=9+4.33333333333/5.44444444444
$